Are you looking for the best NCERT solutions for class 8 maths chapter 1 exercise 1.1? If your answer is yes, you visited the right website (Skill Awesome).
Rational numbers class 8 Exercise 1.1 provides a comprehensive study of concepts and formulas related to rational numbers and a variety of questions and problems to test students’ understanding of rational numbers. This chapter is an essential part of the syllabus for class 8 maths. Because it lays the foundation for understanding other mathematical concepts and operations. Which students will have to face in higher classes?
The questions in this exercise cover a wide range of topics, including identifying rational and irrational numbers, converting fractions to decimals, and performing arithmetic operations with rational numbers.
It is an excellent resource for the students as we provide solutions to all the questions one by one. The solutions are written in a clear and concise manner, making it easy for the students to understand and follow.
Let’s find out all the answers to ncert solutions for class 8 maths chapter 1
What is rational numbers?
In my opinion, a rational number is a fractional number, where we put the numerator and denominator as integers, and the denominator is not equal to zero. It is part of the real number system, which also includes irrational numbers, such as the square root of 2 or pi.
In 8th-grade math, students learn about rational numbers and their properties, including how to add, subtract, multiply, and divide them. They also learn about equivalent fractions and simplifying fractions. Understanding it is an important foundation for more advanced mathematical concepts, such as algebra and calculus.
Let’s start with ncert solutions for class 8 Maths chapter 1
NCERT Solutions for Class 8 Maths Chapter 1 Exercise 1.1 Solutions
Q1. Using appropriate properties find.
Q2. Write the additive inverse of each of the following:
Q3. Verify that: -(-x) = x for:
Q4. Find the multiplicative inverse of the following:
Q5. Name the property under multiplication used in each of the following:
Q6. Multiply 6/13 by the reciprocal of -7/16:
Q7. Tell what property allows you to compute:
Q8. Is 8/9 the multiplicative inverse of -1+(1/8) ? Why or Why not?:
Q9. If 0.3 the multiplicative inverse of 3+(1/3) ? Why or why not?:
Q11. Fill in the blanks:
- Chapter 1 Ex 1.2 Solutions
- Rational Numbers Key Facts
- MCQ Questions & Answers
- Extra Questions
- Online Test
FAQ on NCERT solutions for class 8 maths chapter 1
Write three rational numbers between 2 and 3.
Three rational numbers between 2 and 3 could be:
Represent the rational number -5/6 on the number line.
To represent -5/6 on the number line, follow these steps:
- Draw a horizontal line and mark a point O as the origin.
- Move 5 units to the left of the origin (since the number is negative), and mark a point A.
- Divide the distance between O and A into six equal parts.
- Mark point B on the number line corresponding to -5/6, which will be five-sixths of the distance between O and A.
- Draw a line segment from O to B.
Add the rational numbers: 2/3 + 5/4
To add the rational numbers, we need to find a common denominator.
2/3 + 5/4 = (8/12) + (15/12) = 23/12
Subtract the rational numbers: 7/8 – 3/4
To subtract the rational numbers, we need to find a common denominator.
7/8 – 3/4 = (7/8) – (6/8) = 1/8
Find the product of the rational numbers: 3/5 * 4/7.
To find the product of the rational numbers, multiply the numerators and denominators.
(3/5) * (4/7) = (12/35)
Divide the rational numbers: 2/3 ÷ 4/5.
To divide the rational numbers, multiply the first fraction by the reciprocal of the second fraction.
(2/3) ÷ (4/5) = (2/3) * (5/4) = 10/12 = 5/6
Express 0.625 as a rational number in the form of p/q.
To express 0.625 as a rational number, we can write it as 625/1000 and then simplify it.
0.625 = 625/1000 = 5/8
If x is a rational number and x + 3 = 7/2, find the value of x.
To find the value of x, isolate x on one side of the equation.
- x + 3 = 7/2
- x = 7/2 – 3 = 7/2 – 6/2 = 1/2
Solve the equation for x: 2x/3 = 4/5.
To solve the equation, isolate x on one side of the equation.
- 2x/3 = 4/5
- 2x = (4/5) * 3
- 2x = 12/5
- x = (12/5) / 2
- x = 12/10
- x = 6/5
A certain temperature on a winter day is represented as -12/5 degrees Celsius. What would this temperature be in degrees Fahrenheit? (Assume the Fahrenheit to Celsius conversion formula: F = (9/5)C + 32).
To convert Celsius to Fahrenheit, use the given formula.
- F = (9/5)C + 32
- F = (9/5) * (-12/5) + 32
- F = -108/25 + 32
- F = (-108 + 800)/25
- F = 692/25 ≈ 27.68 degrees Fahrenheit (rounded to two decimal places)